0=8t^2+11t-56

Solution for 0=8t^2+11t-56 equation:

0=8t^2+11t-56

We move all terms to the left:

0-(8t^2+11t-56)=0

We add all the numbers together, and all the variables

-(8t^2+11t-56)=0

We get rid of parentheses

-8t^2-11t+56=0

a = -8; b = -11; c = +56;
Δ = b2-4ac
Δ = -112-4·(-8)·56
Δ = 1913
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{1913}}{2*-8}=\frac{11-\sqrt{1913}}{-16}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{1913}}{2*-8}=\frac{11+\sqrt{1913}}{-16}
$